隐写术总结

时间：2015-02-12　|　来源：互联网　|　阅读：172

话题：

1111111000100001101111111100000101110010110100000110111010100000000010111011011101001000000001011101101110101110110100101110110000010101011011010000011111111010101010101111111000000001011101110000000011010011000001010011101101111010101001000011100000000000101000000001001001101000100111001111011100111100001110111110001100101000110011100001010100011010001111010110000010100010110000011011101100100001110011100100001011111110100000000110101001000111101111111011100001101011011100000100001100110001111010111010001101001111100001011101011000111010011100101110100100111011011000110000010110001101000110001111111011010110111011011

得到的01 串的长度是625，除以8 除以7 都无法整除，也就是说没法直接转换成ascii码。

图片16.png

然后发现625 = 25*25，刚好是个正方形的形状，那么尝试一下把这些01 组成一个正方形看看是什么，可以用python的PIL编程可以很方便的画图，在kali自带就可以有，win的环境需要安装PIL的第三方库。

#!/usr/bin/env python

importImage

MAX=25

pic=Image.new("RGB",(MAX,MAX))

str="1111111000100001101111111100000101110010110100000110111010100000000010111011011101001000000001011101101110101110110100101110110000010101011011010000011111111010101010101111111000000001011101110000000011010011000001010011101101111010101001000011100000000000101000000001001001101000100111001111011100111100001110111110001100101000110011100001010100011010001111010110000010100010110000011011101100100001110011100100001011111110100000000110101001000111101111111011100001101011011100000100001100110001111010111010001101001111100001011101011000111010011100101110100100111011011000110000010110001101000110001111111011010110111011011"

i=0

foryinrange(0,MAX):

forxinrange(0,MAX):

if(str[i]=='1'):

pic.putpixel([x,y],(0,0,0))

else:

pic.putpixel([x,y],(255,255,255))

i=i+1

pic.show()

pic.save("flag.png")